Posted in Python onMay 06, 2021
看代码吧~
# -*- coding:utf-8 -*-
#python 2.7
#http://tieba.baidu.com/p/2460150866
#标签操作
from bs4 import BeautifulSoup
import urllib.request
import re
#如果是网址，可以用这个办法来读取网页
#html_doc = "http://tieba.baidu.com/p/2460150866"
#req = urllib.request.Request(html_doc)
#webpage = urllib.request.urlopen(req)
#html = webpage.read()
html="""
<html><head><title>The Dormouse's story</title></head>
<body>
<p class="title" name="dromouse"><b>The Dormouse's story</b></p>
<p class="story">Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" class="sister" id="xiaodeng"><!-- Elsie --></a>,
<a href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" rel="external nofollow" class="sister" id="link3">Tillie</a>;
<a href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" class="sister" id="xiaodeng">Lacie</a>
and they lived at the bottom of a well.</p>
<p class="story">...</p>
"""
soup = BeautifulSoup(html, 'html.parser') #文档对象
#查找a标签,只会查找出一个a标签
#print(soup.a)#<a class="sister" href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" id="xiaodeng"><!-- Elsie --></a>
for k in soup.find_all('a'):
print(k)
print(k['class'])#查a标签的class属性
print(k['id'])#查a标签的id值
print(k['href'])#查a标签的href值
print(k.string)#查a标签的string
如果，标签<a>中含有其他标签，比如<em>..</em>，此时要提取<a>中的数据，需要用k.get_text()
soup = BeautifulSoup(html, 'html.parser') #文档对象
#查找a标签,只会查找出一个a标签
for k in soup.find_all('a'):
print(k)
print(k['class'])#查a标签的class属性
print(k['id'])#查a标签的id值
print(k['href'])#查a标签的href值
print(k.string)#查a标签的string
如果，标签<a>中含有其他标签，比如<em>..</em>，此时要提取<a>中的数据，需要用k.get_text()
通常我们使用下面这种模式也是能够处理的，下面的方法使用了get()。
html = urlopen(url)
soup = BeautifulSoup(html, 'html.parser')
t1 = soup.find_all('a')
print t1
href_list = []
for t2 in t1:
t3 = t2.get('href')
href_list.append(t3)
补充：python爬虫获取任意页面的标签和属性（包括获取a标签的href属性）
看代码吧~
# coding=utf-8
from bs4 import BeautifulSoup
import requests
# 定义一个获取url页面下label标签的attr属性的函数
def getHtml(url, label, attr):
response = requests.get(url)
response.encoding = 'utf-8'
html = response.text
soup = BeautifulSoup(html, 'html.parser');
for target in soup.find_all(label):
try:
value = target.get(attr)
except:
value = ''
if value:
print(value)
url = 'https://baidu.com/'
label = 'a'
attr = 'href'
getHtml(url, label, attr)
以上为个人经验，希望能给大家一个参考，也希望大家多多支持三水点靠木。如有错误或未考虑完全的地方，望不吝赐教。
python 如何获取页面所有a标签下href的值
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