Python中type的构造函数参数含义说明

测试代码如下：

 class ModelMetaClass(type):

     def __new__(cls,name,base,attrs):

         logging.info("cls is:"+str(cls))

         logging.info("name is:"+str(name))

         logging.info("base is:"+str(base))

         logging.info("attrs is:"+str(attrs))

         return type.__new__(cls,name,base,attrs)

         pass

     pass

 

 class Model(dict):

     __metaclass__ = ModelMetaClass

     def __init__(self):

         pass

     pass

 

 def main():

     m=Model()

 

 if __name__ == '__main__':

     main()

测试结果：

 INFO:root:cls is:<class '__main__.ModelMetaClass'>

 INFO:root:name is:Model

 INFO:root:base is:(<type 'dict'>,)

 INFO:root:attrs is:{'__module__': '__main__', '__metaclass__': <class '__main__.ModelMetaClass'>, '__init__': <function __init__ at 0x025C76F0>}

结论就显而易见了。cls是当前类的名字，即类本身。name是通过__metaclass__属性指向ModelMetaClass的类，即要实例化的类，ModelMetaClass拦截了该类的实例化。base是要实例化的类的基类。attrs是要实例化的类的属性集合。