js 取时间差去掉周六周日实现代码

function GetDayNum(no,type) { 
if (type == "35") { 
var num7 = document.getElementById("6").value; 
var value = document.getElementById("7").value; 
var valueR = num7; 
if (no == "7") {valueR = value;}//标识时间值 
if (num7 != "" && value != "") {//两个时间段可以融合 BUG1 
var numValue = 0; 
var numValue = 0; 
var day = 24 * 60 * 60 * 1000; 
var dateArr = value.split("-"); 
var checkDate = new Date(); 
checkDate.setFullYear(dateArr[0], dateArr[1] - 1, dateArr[2]); 
var checkTime = checkDate.getTime(); 
var dateArr2 = num7.split("-"); 
var checkDate2 = new Date(); 
checkDate2.setFullYear(dateArr2[0], dateArr2[1] - 1, dateArr2[2]); 
var checkTime2 = checkDate2.getTime(); 
var numValue = (checkTime - checkTime2) / day; //相差的总天数 var totleWeek = numValue / 7; //差别多少周 
var yuDay = numValue % 7; //除了整个星期的天数 
var lastDay = 0; 
var startWeek = num7.replace(/-/g, "/"); //把“-”改为“/”，其中“-”算时间不准确这个我测试了 
//var date = new Date(parseInt(startWeek[0]), parseInt(startWeek[1]), parseInt(startWeek[2])); 
var date = Date.parse(startWeek); 
var dateNew = new Date(date); 
var weekDay = dateNew.getDay(); //星期几 
var endWeekDay = 0; //多余的天数有几天是周六或者周日 
if ((weekDay == 6 && yuDay >= 2) || (weekDay == 7 && yuDay >= 1) || (weekDay == 5 && yuDay >= 3) || (weekDay == 4 && yuDay >= 4) || (weekDay == 3 && yuDay >= 5) || (weekDay == 2 && yuDay >= 6) || (weekDay == 1 && yuDay >= 7)) { 
endWeekDay = 2;3water.com 
} 
if ((weekDay == 6 && yuDay < 1) || (weekDay == 7 && yuDay < 5) || (weekDay == 5 && yuDay < 2) || (weekDay == 4 && yuDay < 3) || (weekDay == 3 && yuDay < 4) || (weekDay == 2 && yuDay < 5) || (weekDay == 1 && yuDay < 6)) { 
endWeekDay = 1; 
} 
// if (numValue == 0) { numValue = 1; } 
numValue = numValue - (totleWeek * 2) - endWeekDay; //最终时间 
} 
} 
}